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Question

The sum of infintie terms of a decreasing G.P is equal to the greatest value of the function f(x)=x3+3x9 in the interval [2,3] and the difference between the first two terms is f1(0), common ratio of the G.P is

A
1/3
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B
2/3
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C
4/3
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D
2/3
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Solution

The correct option is B 2/3
f(x)=x3+3x9
f(x)=3x2+3>0
f(x)
Greatest value =f(3)
=27+99
=27
A1R=27 ... (1)
AAR=f(0)=3
A(1R)=3 ... (2)
(1)×(2)
A2=27×3=81
A=9
$ \dfrac{9}{1-R}=27 \Rightarrow l-R=\dfrac{1}{3}$
R=23

1084269_1173248_ans_440c5e208783493b8871e09b1679e8dc.png

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