The correct option is A 3050
L.C.M. of 2 and 5 is 10.
Numbers divisible by 10 will contain numbers which are also divisible by 2 and 5. . Thus the number divisible by 10 will occur twice. Hence we can write S=S2+S5−S10
Now, S2=2.50.512=2550 by ∑n=n(n+1)2
Similarly, S5=1050,S10=550
∴S=S2+S5−S10
=2550+1050−550=3050