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Question

The sum of integral values of n such that equation sinx(2sinx+cosx)=n has at least one real solution is ?

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is A 1
2sin2x+sinxcosx=n
1cos2x+12sin2x=n
sin2x2cos2x=2n1
Range of acosθ+bsinθ is [a2+b2,a2+b2]
Therefore, range of LHS is: [5,5]
52.22, therefore, odd integers in the above range are: {1,1}
Values of n: {0,1}
Sum: 0+1=1

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