The sum of integral values of ′n′ such that equation sinx(2sinx+cosx)=n has at least one real solution is ?
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is A1 2sin2x+sinxcosx=n ⟹1−cos2x+12sin2x=n ⟹sin2x−2cos2x=2n−1 Range of acosθ+bsinθ is [−√a2+b2,√a2+b2] Therefore, range of LHS is: [−√5,√5] √5≈2.22, therefore, odd integers in the above range are: {−1,1} Values of n: {0,1} Sum: 0+1=1