Question

The sum of interior angles of a closed traverse is equal to

• A. $(2n-4){180}^o$
• B. $(3n-4){180}^o$
• C. $(3n-4){90}^o$
• D. $(2n-4){90}^o$

Answer 1

The correct option is D $(2n-4){90}^o$

In closed traverse,

Sum of interior/internal included angles

$=(2n-4)\times {90}^o$

Note : Sum of external included angles = $(2n+4)\times {90}^o$.