Question

The sum of lengths of intercepts of the plane passing through the points (-2, -2, 2 ), (1,1,1) and (1, -1, 2) on the coordinates axes is

• A. 3
• B. 4
• C. 6
• D. 12

Answer 1

The correct option is D 12

Equation of the plane be a (x+2) + b(y+2) +c (z-2) = 0. As it passes through (1, 1, 1) and $(1,-1,2),\frac{a}{1}=\frac{b}{-3}=\frac{c}{-6}.$ Equation of the plane is $\frac{x}{-8}+\frac{y}{\frac{8}{3}}+\frac{z}{\frac{8}{6}}=1$ and the required sum = 12.