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Byju's Answer
Standard VII
Mathematics
Properties of Addition and Subtraction
The sum of le...
Question
The sum of letters in the word MATHS = 2002
Find the base (less than 10) and the number for each letter. Assuming a set of twenty six consecutive non-negative integers represent letter of alphabet
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Solution
It
is
givn
that
,
M
+
A
+
T
+
H
+
S
=
2002
Note
that
,
2002
3
=
2
×
3
3
+
0
×
3
2
+
0
×
3
1
+
2
×
3
0
=
56
2002
4
=
2
×
4
3
+
0
×
4
2
+
0
×
4
1
+
2
×
4
0
=
130
2002
5
=
2
×
5
3
+
0
×
5
2
+
0
×
5
1
+
2
×
5
0
=
252
2002
6
=
2
×
6
3
+
0
×
6
2
+
0
×
6
1
+
2
×
6
0
=
434
2002
7
=
2
×
7
3
+
0
×
7
2
+
0
×
7
1
+
2
×
7
0
=
688
2002
8
=
2
×
8
3
+
0
×
8
2
+
0
×
8
1
+
2
×
8
0
=
1026
2002
9
=
2
×
9
3
+
0
×
9
2
+
0
×
9
1
+
2
×
9
0
=
1460
Since
it
is
assumed
that
a
set
of
twenty
six
consecutive
non
negative
integers
represents
letter
of
alphabet
.
So
it
implies
that
,
MATHS
=
A
+
12
+
A
+
A
+
19
+
A
+
7
+
A
+
18
=
5
A
+
56
Take
A
=
0
and
A
=
194
5
0
+
56
=
56
5
194
+
56
=
1026
So
the
possible
forms
for
integral
A
are
only
56
and
1026
So
we
can
have
base
3
with
A
=
0
and
base
8
with
A
=
194
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