CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The sum of letters in the word MATHS = 2002
Find the base (less than 10) and the number for each letter. Assuming a set of twenty six consecutive non-negative integers represent letter of alphabet

Open in App
Solution

It is givn that, M+A+T+H+S=2002Note that, 20023=2×33+0×32+0×31+2×30=56 20024=2×43+0×42+0×41+2×40=130 20025=2×53+0×52+0×51+2×50=252 20026=2×63+0×62+0×61+2×60=434 20027=2×73+0×72+0×71+2×70=688 20028=2×83+0×82+0×81+2×80=1026 20029=2×93+0×92+0×91+2×90=1460Since it is assumed that a set of twenty six consecutive non negative integers represents letter of alphabet.So it implies that, MATHS=A+12+A+A+19+A+7+A+18 =5A+56Take A=0 and A=194 50+56 =56 5194+56 =1026So the possible forms for integral A are only 56 and 1026So we can have base 3 with A=0 and base 8 with A=194

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Addition and Subtraction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon