The sum of n terms of an A.P. is $3 n^{2} + 4 n$ , the $n^{t h}$ term is

2n-1

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2n+1

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6n-1

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6n+1

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Solution

The correct option is D
6n+1

$n^{t h}$ term = $S_{n} - S_{n - 1}$ = 6n+1

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