The sum of 'n' terms of an A.P. is given by $3 n^{2}$ + $5 n$ then what is the value of $29^{t h}$ term

146

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176

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342

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174

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Solution

The correct option is B 176
$S_{n} = 3 n^{2} + 5 n$

$S_{1} = a_{1} = 3 + 5 = 8$

$S_{2} = 3 (2)^{2} + 5 (2) = 22$

$a_{1} + a_{2} = 22$

$8 + a_{2} = 22$

$a_{2} = 14$

Therefore, $d = a_{2} - a_{1} = 14 - 8 = 6$

Hence,

$a_{29} = a + 28 d = 8 + 28 (6) = 176$

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Similar questions

n

A . P .

3 n^{2} + 5 n

A . P .

152

n

3 n^{2} + 5 n

T_{m} = 164

3 n^{2} + 5 n

T_{m} = 164

S n = 3 n^{2} + 5 n

If the sum of n terms of an A.P. is 3 $n^{2}$ + 5n and $T_{m}$ = 164 then m = ?

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