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Question

The sum of n terms of an AP is 4pn(n+3).The sum of squares of these terms is:


A

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B

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C

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D

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Solution

The correct option is B


Suppose the AP is 1,2,3

At n=1, sum =1

4(p)(1)(4)=1 p =116

Sum of squares = 12= 1 itself

Look for 1 in the answer options

Only at option b

323×1256×(24)=1

Answer is option (b)


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