Question

The sum of n terms of an AP is 4pn(n+3).The sum of squares of these terms is:

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Suppose the AP is 1,2,3

At n=1, sum =1

4(p)(1)(4)=1 $\Rightarrow$ p =$\frac{1}{16}$

Sum of squares = $1^2$= 1 itself

Look for 1 in the answer options

Only at option b

$\frac{32}{3}\times \frac{1}{256}\times \left(24\right)=1$

Answer is option (b)