The sum of n terms of an arithmetic progression (AP) is $3 n^{2} - n$ .

(ii) The nth term of this AP is:

[1 mark]

6n + 8

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6n - 4

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6n - 2

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6n + 4

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Solution

The correct option is B 6n - 4
Let a be the first term of the AP, and d be the common difference.
$T_{n}$ = a +(n-1)d
$T_{n}$ = 6n-4

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