The sum of n terms of an arithmetic progression (AP) is $3 n^{2} - n$ .

(iii) The sum of first thirteen terms of this AP is:

[1 mark]

594

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494

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484

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394

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Solution

The correct option is B 494
Given,
$S_{n} = 3 n^{2} - n$
By putting $n = 13$ , we get,
$S_{13} = 3 (13)^{2} - 13 = 494$

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