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Question

The sum of n terms of an arithmetic sequence can be calculated by .........................

A
Sn=n2[2a+(n1)d]
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B
Sn=n2[2a+(n+1)d]
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C
Sn=2n2[2a+(n1)d]
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D
Sn=2n2[2a(n1)d]
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Solution

The correct option is A Sn=n2[2a+(n1)d]
The sum of n terms of an arithmetic sequence can be calculated by Sn=n2[2a+(n1)d]
Where, n denotes the total number of terms
a = first term
d = common difference
Sn = Sum of n terms

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