The sum of n terms of an arithmetic sequence can be calculated by .........................
A
Sn=n2[2a+(n−1)d]
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B
Sn=n2[2a+(n+1)d]
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C
Sn=2n2[2a+(n−1)d]
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D
Sn=2n2[2a−(n−1)d]
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Solution
The correct option is ASn=n2[2a+(n−1)d] The sum of n terms of an arithmetic sequence can be calculated by Sn=n2[2a+(n−1)d] Where, n denotes the total number of terms a = first term d = common difference Sn = Sum of n terms