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Question

The sum of n terms of series (11n)+(12n)+(13n)+............. will be:

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Solution

Let,Sn=(11n)+(12n)+(13n)+.............n terms .
Sn=n(1n+2n+3n+....+nn)
=n(1+2+3+.......+nn)
=nn(n+1)2n [Since, 1+2+3+......+n=n(n+1)2]
=nn+12
=n12




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