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Question

The sum of n terms of the sequence loga,logar,logar2,... is

A
n2loga2rn1
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B
nloga2rn1
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C
3n2loga2rn1
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D
None of these
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Solution

The correct option is A n2loga2rn1
The given sequence can be expressed as loga,(loga+logr),(loga+2logr),...
which is clearly an A.P. whose first term is loga and common difference is logr
The nth term =loga+(n1)logr
Since sum to n terms =n2(a1+an)
Sn=n2[loga+loga+(n1)logr]
=n2[2loga+(n1)logr]=n2loga2rn1

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