The sum of non-integeral roots of the equation x4−3x3−2x2+3x+1=0 is
A
3
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B
0
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C
−3
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D
6
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Solution
The correct option is A3 Divide the given equation by x2⇒x2−3x−2+3x+1x2=0 ⇒(x2+1x2)−3(x−1x)−2=0
Now put x−1x=y ⇒(y2+2)−3y−2=0⇒y2−3y=0⇒y=0,3
Case I: x−1x=0⇒x=±1
Case II: x−1x=3⇒x=12(3±√13)