The sum of numbers between 100 and 500, which are divisible by 6, is:

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498

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2010

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20100

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Solution

The correct option is D
20100

Numbers divisible by 6 between 100 and 500

$S_{n}$ = 102 + 108 + 114 + .......+ 498.

If there are n terms in $s_{n}$ , then

498 = 102 + (n - 1). 6 ⇒ n = 67.

∴ $S_{n}$ = $\frac{1}{2}$ (67)(102 + 498) = 20100.

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