Question

The sum of oxidation number of nitrogen in $N{H}_{4}N{O}_3$ is:

• A. 1
• B. 2
• C. 4
• D. none of these

Answer 1

Answer: (B)

2

Given $N{H}_{4}N{O}_3$ in the ionic state is present in the form of $N{H}_4^{+}+{N{O}_3}^{-}$.

$\Rightarrow x+4=+1$ $\Rightarrow x-6=-1$

$\Rightarrow x=-3$ $\Rightarrow x=+5$

Sum of two oxidation states of $N$ gives $+2$ .