Question

The sum of p orbitals involved in the hybridisation of $N{H}_3$ and $B{F}_3$ molecules are:

• A. $6$
• B. $5$
• C. $4$
• D. $3$

Answer 1

The correct option is B $5$

In $N{H}_3$, $N$ is bonded to three H atoms and also has a lone pair. Thus,it is $s{p}^3$ hybridised.
In $B{F}_3$, $B$ is bonded to three F atoms has no lone pair. Thus,it is $s{p}^2$ hybridised.
The hybridisation of $N{H}_3$ and $B{F}_3$ are $s{p}^3$ and $s{p}^2$ respectively.
Hence,a total of $5$ $p$ orbitals are involved in the hybridisation of both the molecules.