The sum of possible real values of b for which the equations 2017x2+bx+7102=0 and 7102x2+bx+2017=0 have a common root, is
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Solution
Let the common root be α ⇒2017α2+bα+7102=0⋯(1) and 7102α2+bα+2017=0⋯(2) Subtracting (2) from (1), we get −5085α2+5085=0 ⇒α2=1 ⇒α=±1 If α=+1,b=−9119 If α=−1,b=9119 ∴ Sum of all possible values of b is 0.