The sum of present ages of a father and his son is $50$ years. After $5$ years, the age of father becomes thrice the age of his son. Find their present ages.

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Solution

We have sum of present ages father and son as $a + b = 50$ , the age of father becomes thrice the age of son after $5$ years,
$a + 5 = 3 (b + 5)$ . Solving two equations
$a + b = 50$ and $a - 3 b = 10$ we get $b = 10$ and $a = 40$ .
The present age of father is $40$ years and of son is $10$ years.

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The sum of present ages of a father and his son is 50 years. After 5 years, the age of father becomes thrice the age of his son. Find their present ages.

We have sum of present ages father and son as a+b=50, the age of father becomes thrice the age of son after 5 years,a+5=3(b+5). Solving two equationsa+b=50 and a−3b=10 we get b=10 and a=40.The present age of father is 40 years and of son is 10 years.

The sum of present ages of a father and his son is $50$ years. After $5$ years, the age of father becomes thrice the age of his son. Find their present ages.

We have sum of present ages father and son as $a + b = 50$ , the age of father becomes thrice the age of son after $5$ years,
$a + 5 = 3 (b + 5)$ . Solving two equations
$a + b = 50$ and $a - 3 b = 10$ we get $b = 10$ and $a = 40$ .
The present age of father is $40$ years and of son is $10$ years.