The sum of rational term in the expansion of (315+213)15 is
Given that ,
(315+213)15
General term is
tr+1=15Cr(315)15−r(213)r
=15Cr.315−r5.2r3
For general term r=0,5
t0+1=15C0.33=27
t15+1=t16=15C1530.25 =32
Hence, this is the required value = 27+32=59