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Question

The sum of residues of f(z)=2z(z1)2(z2) at its singular point is

A
8
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B
4
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C
0
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D
4
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Solution

The correct option is C 0
f(z)=2z(z1)2(z2)
Poles are z=2 (simple pole) and z=1 (double pole)
R1=Resf(z)(z =2)=limz2(z2)f(z)=limz2(2z(z1)2]=4R2=Resf (z)(z=1)=1(21!)(ddz(z1)2f(z)]z=1=[ddz(2zz2)]z=1=4
Hence sum of residues=R1+R2=0

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