The sum of six consecutive numbers is 150. Find the first number
A
20.1
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B
22.5
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C
20.5
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D
21.5
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Solution
The correct option is D22.5 5 consecutive numbers form an arithmetic progression with difference 1. n=6,s6=150,d=1 Using the formula, Sn=n2[2a+(n−1)d] Therefore, 150=62[2a+(6−1)1] ⇒150=3[2a+5]