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Question

The sum of six consecutive numbers is 150. Find the first number

A
20.1
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B
22.5
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C
20.5
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D
21.5
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Solution

The correct option is D 22.5
5 consecutive numbers form an arithmetic progression with difference 1.
n=6,s6=150,d=1
Using the formula, Sn=n2[2a+(n1)d]
Therefore, 150=62[2a+(61)1]
150=3[2a+5]
a=452=22.5
Thus the first number is 22.5.

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