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Byju's Answer
Standard XII
Mathematics
De Morgan's Law
The sum of so...
Question
The sum of solutions of the equation
∣
∣ ∣
∣
1
4
20
1
−
2
5
1
2
x
5
x
2
∣
∣ ∣
∣
=
0
is ..........
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Solution
∣
∣ ∣
∣
1
4
20
1
−
2
5
1
2
x
5
x
2
∣
∣ ∣
∣
=
0
⇒
1
(
−
10
x
2
−
10
x
)
−
4
(
5
x
2
−
5
)
+
20
(
2
x
+
2
)
=
0
⇒
−
30
x
2
+
30
x
+
60
=
0
⇒
(
x
−
2
)
(
x
+
1
)
=
0
⇒
x
=
2
,
−
1
Hence the sum of solution is
2
−
1
=
1
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0
Similar questions
Q.
The solution set of the equation
∣
∣ ∣
∣
1
4
20
1
−
2
5
1
2
x
5
x
2
∣
∣ ∣
∣
=
0
, is
Q.
Using factor theorem, find the solution set of the equation
∣
∣ ∣
∣
1
4
20
1
−
2
5
1
2
x
5
x
2
∣
∣ ∣
∣
=
0
Q.
Find the roots of equation
∣
∣ ∣
∣
1
4
20
1
−
2
5
1
2
x
5
x
2
∣
∣ ∣
∣
=
0
.
Q.
The roots of the equation
∣
∣ ∣
∣
1
4
20
1
−
2
5
1
2
x
5
x
2
∣
∣ ∣
∣
=
0
are
Q.
Find the value of
x
in the equation
∣
∣ ∣
∣
1
4
20
1
−
2
5
1
2
x
5
x
2
∣
∣ ∣
∣
=
0
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