The sum of squares of deviation of variates from their A. M. is always:

Zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Minimum

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Maximum

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Nothing can be said

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Minimum
It is fundamental concept that sum of squares of deviation of any variate from their A.M is always minimum.

Suggest Corrections

Similar questions

\sum (x_{i} - ¯ ¯ ¯ x) = 0

\sum (x_{i} - ¯ ¯ ¯ x) = 0^{2}

10

50

250

State with reason whether the following statements are True or False:

(i) Sum of square of the deviations of items from their arithmetic mean is the maximum.

(ii) Standard Deviation is based on all values.

(iii) For a given set of observations, standard deviation is always more than mean deviation from mean.

Join BYJU'S Learning Program