MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Standard Deviation

The sum of sq...

Question

The sum of squares of difference between ranks obtained in English and Economics of 10 students is 33. Calculate rank correlation coefficient.

Open in App

Solution

$R = 1 - \frac{6 \sum D^{2}}{N^{3} - N} = 1 - \frac{6 \times 33}{10^{3} - 10} = 1 - \frac{198}{990} = 0.80$

Suggest Corrections

thumbs-up

9

Similar questions

Q. The coefficient of rank correlation of the marks obtained by 10 students in two particular subjects was found to be 0.5. It was later discovered that the difference in ranks in two subjects obtained by one of the students was wrongly taken as 3 instead of 7. What should be the correct value of coefficient of rank correlation.

Q. If the rank correlation coefficient is

0.6

and the sum of squares of difference of ranks is

66

, then find the number pairs of observations.

\sum d_{i}^{2} = 25

n = 6

find rank correlation coefficient where

d_{i}

is the difference between the ranks of

i^{t h}

Give the formula to calculate rank correlation coefficient with
(i) non-repeated ranks and
(ii) repeated ranks

Q. Following are the ranks of

10

students in Maths and Biology projects given by

2

professors. Find the rank correlation coefficient.

Maths	4	8	5	3	1	2	10	7	6	9
Biology	1	4	5	6	2	3	8	9	7	10

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Measure of Dispersion

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard Deviation

Standard XI Mathematics

Join BYJU'S Learning Program

CrossIcon