Question

The sum of squares of first ten natural numbers

• A. $375$
• B. $385$
• C. $475$
• D. $485$

Answer 1

Answer: (B)

$385$

Sum of squares of first natural numbers $=\frac{n(n+1)(2n+1)}{6}$

Here, $n=10$

$\therefore Sum=$$\frac{10\left(11\right)\left(21\right)}{6}=5\times 11\times 7=385$