Question

The sum of squares of successive integers 8 to 16, both inclusive, will be

• A.
  1126
• B.
  1174
• C.
  1292
• D.
  1356

Answer 1

The correct option is D

1356
Apply formula $\Sigma n^2$ to solve this question where

$\Sigma n^2=\frac{n(n+1)(2n+1)}{6}$

${\sum }_{n=1}^{n=16}{n}^2-{\sum }_{n=1}^{n=7}{n}^2$

$=\frac{16(16+1)(32+1)}{6}-\frac{7(7+1)(14+1)}{6}$

= 1496 - 140 = 1356