Question

The sum of squares of the intercepts on the coordinate axes made by the tangent to $x^{1/3}+y^{1/3}=a^{1/3}at(\frac{a}{8},\frac{a}{8})$ is 2, and a > 0 then a = ____

• A. 2
• B. 4
• C. 2√2
• D. 8

Answer 1

The correct option is B

4

$\text{Tgt is}\frac{x}{\frac{a}{4}}+\frac{y}{a/4}=1\frac{a^2}{16}+\frac{a^2}{16}=2a=\pm 4$