The sum of the 2rd term and the 7th term of an A. P. is 30. If its 15th term is 1 less than twice of its 8th term, find the A. P.
Given
a2+a7=30a+d+a+6d=302a+7d=30−−−−(1)a15=2a8−1a+14d=2(a+7d)−1a+14d=2a+14d−1a=1Put in (1)2(1)+7d=307d=28d=4AP:1,5,9,13,…