Question

The sum of the $4^{th}$ & $8^{th}$ terms of an AP is $24$ & the sum of the $6^{th}$ & $1$ terms is $44$. Find the $3$ terms of an AP.

Answer 1

a4+a8=24

a+3d+a+7d=24

2a+10d=24------->eq.1

a6+a10=44

a+5d+a+9d=44

2a+14d=44------>eq.2

From eq.1 and eq.2

2a+10d=24

2a+14d=44

-----------------

-4d=-20

d=5

Subs d=5 in eq.1

2a+10(5)=24

2a+50=24

2a=-26

a= -13

A.P:-13,-13+5=-8,-8+5=-3

-13,-8,-3