The sum of the $4^{t h}$ and the $8^{t h}$ terms of an A.P. is $24$ and the sum of $7^{t h}$ and the $10^{t h}$ terms is $44$ . Find the first three terms of the arithmetic progression.

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Solution

$a_{4} + a_{8} = 24$
$a_{7} + a_{10} = 44$
$a + 3 d + a + 7 d = 24 . . . . . . . . . . . (1) a + 6 d + a + 9 d = 44 . . . . . . . . . . . . . (2) (1) - (2) - 5 d = - 20 d = 4 a = - 8$
$∴ A P$ is $- 8, - 4, 0, 4.....$

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Q. Question 18
The sum of

4^{t h}

and

8^{t h}

terms of an A.P. is 24 and the sum of the

6^{t h}

and

10^{t h}

terms is 44. Find the first three terms of the A.P.

Q. Question 18
The sum of

4^{t h}

and

8^{t h}

terms of an A.P. is 24 and the sum of the

6^{t h}

and

10^{t h}

terms is 44. Find the first three terms of the A.P.

Q. The sum 4^th and 8^th terms of an A.P. is 24 and the sum of 6^th and 10^th terms is 44. Find the A.P.

The sum of the $4^{th}$ and $8^{th}$ term of an A.P is $24$ and the sum of its $6^{th}$ and $10^{th}$ terms is $44$ . Find the first term?

The sum of the $4^{t h}$ and $8^{t h}$ terms of an AP is 24 and the sum of $6^{t h}$ and $10^{t h}$ terms is 44. Find the first three terms of the AP.

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The sum of the 4th and the 8th terms of an A.P. is 24 and the sum of 7th and the 10th terms is 44. Find the first three terms of the arithmetic progression.

a4+a8=24 a7+a10=44a+3d+a+7d=24...........(1)a+6d+a+9d=44.............(2)(1)−(2)−5d=−20d=4a=−8∴AP is −8,−4,0,4.....

The sum of the $4^{t h}$ and the $8^{t h}$ terms of an A.P. is $24$ and the sum of $7^{t h}$ and the $10^{t h}$ terms is $44$ . Find the first three terms of the arithmetic progression.

$a_{4} + a_{8} = 24$
$a_{7} + a_{10} = 44$
$a + 3 d + a + 7 d = 24 . . . . . . . . . . . (1) a + 6 d + a + 9 d = 44 . . . . . . . . . . . . . (2) (1) - (2) - 5 d = - 20 d = 4 a = - 8$
$∴ A P$ is $- 8, - 4, 0, 4.....$