Let a be the first term and d be the common difference of the given A.P.
Then,
a5+a7=52
a10=46
a+4d+a+6d=52 and
a+9d=46
⇒2a+10d=52....(1)
a+9d=46....(2)
multiplying (2) equation by 2 and we get,
2a+18d=92....(3)
now subtract (1) from (3) then we get,
8d=40
⇒d=5
now put d in (1) equation we get
a=1
There for the given series is
a,a+d,a+2d,a+3d...
i.e. 1,6,11,16...