Question

The sum of the acute angles of an obtuse triangle ${70}^o$ and their difference is ${10}^o$. The bigger acute angle is:

• A. ${40}^o$
• B. ${70}^o$
• C. ${110}^o$
• D. ${30}^o$

Answer 1

The correct option is A ${40}^o$

$x+y=70$
$x-y=10$
$+++$
$2x=80$
$x=40$
Since, $x-y=10$, we get y = 30