Question

The sum of the angles of a polygon is ${8100}^0$. How many sides does it have? [2 Marks]

Answer 1

Sum of inner angles of a polygon $=(n-2)\times {180}^0$
$={8100}^0$ [1 Mark]
$\Rightarrow 180n-{360}^0={8100}^0$
$\Rightarrow 180n={8460}^0$
$\Rightarrow n=\frac{8460}{180}=47$
Number of sides =47 [1 Mark]