The sum of the coefficients in the expansion of $(1 + x - 3 x^{2})^{3148}$ is

2^{3148}

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Solution

The correct option is C $1$
The sum of coefficients in the expansion $(1 + x - 3 x^{2})^{3148}$ can be found by substituting $x$ as $1.$
We will get $(1 + 1 - 3)^{3148} = (- 1)^{3148} = 1$

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{(1 + x - 3 x^{2})}^{2163}

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