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Question

The sum of the coefficients of all odd degree terms in the expansion of (x+x31)5+(xx31)5 ,(x>1) is

A
1
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B
0
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C
1
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D
2
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Solution

The correct option is D 2
=2(5C0x5+ 5C2x3(x31)+ 5C4x(x31)2)
=2(x5+10(x6x3)+5(x)(x6+12x3))
Sum of coefficients of odd powers =2(110+10)=2

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