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Question

The sum of the coefficients of all odd exponets of x in the product of (1x+x2x3+x4+...x49+x50)×(1+x+x2+x3+...+x50) equals

A
1
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B
0
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C
1
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D
None of these
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Solution

The correct option is B 0
Coefficient of x1 will be
1+(1)
=0 ..(i)
Coefficient of x3 will be
1+(1)+1+(1)
=0
Hence the coefficients of xn where n is odd is zero.

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