The sum of the coefficients of all reactants and products Fe 2 O 3 s-Cs- Fes- CO 2 g after balancing the equation is -

The correct option is A 12 Fe _ 2 O _ 3 (s)+C(s)→ Fe(s)+ CO _ 2 (g) Number of iron(Fe) atoms: 2 on LHS, 1 on RHSNumber of carbon(C) atoms: 1 on the L ...

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Standard VIII

Chemistry

Writing Chemical Equation

The sum of th...

Question

The sum of the coefficients of all reactants and products ${F e}_{2} O_{3} (s) + C (s) \to F e (s) + {C O}_{2} (g)$ after balancing the equation is :

12

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Solution

The correct option is A $12$
${F e}_{2} O_{3} (s) + C (s) \to F e (s) + {C O}_{2} (g)$
Number of iron(Fe) atoms: 2 on LHS, 1 on RHS
Number of carbon(C) atoms: 1 on the LHS, 1 on RHS
Number of oxygen (O) atoms: 3 on the LHS, 2 on the RHS
Since we have an odd number of oxygens, we should balance,
Multiply by 2
${2 F e}_{2} O_{3} (s) + C (s) \to F e (s) + {C O}_{2} (g)$
Lets balance the oxygen on the other side by multiplying by 3
${2 F e}_{2} O_{3} (s) + C (s) \to F e (s) + 3 {C O}_{2} (g)$
Balancing the carbon by multiplying by 3 on LHS
${2 F e}_{2} O_{3} (s) + 3 C (s) \to F e (s) + {3 C O}_{2} (g)$
Finally, balance the iron by multiplying by 4 on LHS
${2 F e}_{2} O_{3} (s) + 3 C (s) \to 4 F e (s) + {3 C O}_{2} (g)$
The sum of the coefficients is 2+3+4+3=12

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Similar questions

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The sum of the coefficients of all reactants and products Fe2O3(s)+C(s)→Fe(s)+CO2(g) after balancing the equation is :

The sum of the coefficients of all reactants and products ${F e}_{2} O_{3} (s) + C (s) \to F e (s) + {C O}_{2} (g)$ after balancing the equation is :