The sum of the coefficients of the first 10 terms in the expansion of (1−x)−3
A
220
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B
286
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C
120
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D
150
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Solution
The correct option is A220 For (1−x)−3, the sum of the first r terms will be n+r−1Cn Replacing n=3 and r=10 in the above formula, we get 3+10−1C3 =12C3 =12.11.103! =12.11.106 =2.11.10 =220