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Question

The sum of the coefficients of the first 10 terms in the expansion of (1−x)−3

A
220
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B
286
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C
120
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D
150
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Solution

The correct option is A 220
For (1x)3, the sum of the first r terms will be
n+r1Cn
Replacing n=3 and r=10 in the above formula, we get
3+101C3
=12C3
=12.11.103!
=12.11.106
=2.11.10
=220

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