Question

The sum of the crystal field stabilisation energy of high spin and low spin $d^6$ metal ion in octahedral field is calculated as $x{\Delta }_o$. The value of $|x|=$

Answer 1

For high spin complex with $d^6$ configuration
$CFSE=(-0.4\times (t_{2g})e^{-}+0.6\times (e_g\left)e^{-}\right){\Delta }_o$
$CFSE=(-0.4\times (4)e^{-}+0.6\times (2\left)e^{-}\right){\Delta }_o$
$CFSE=(-0.4){\Delta }_o$

For low spin complex with $d^6$ configuration
$CFSE=(-0.4\times (t_{2g})e^{-}+0.6\times (e_g\left)e^{-}\right){\Delta }_o$
$CFSE=(-0.4\times (6)e^{-}+0.6\times (0\left)e^{-}\right){\Delta }_o$
$CFSE=(-2.4){\Delta }_o$

$CFS{E}_{\text{total}}=\left(\right(-2.4)+(-0.4\left)\right){\Delta }_o$
$CFS{E}_{\text{total}}=(-2.8){\Delta }_o$