The sum of the cubes of first 8 natural numbers is

1269

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1298

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1296

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1297

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
1296

The sum of the cubes of first n natural numbers is given by $\frac{n^{2} (n + 1)^{2}}{4}$

Substituting n=8 , we get sum as 1296.

Suggest Corrections

Similar questions

What is the sum of the cubes of the first 7 natural numbers?

Find the sum of the cubes of the first $n$ natural numbers.

The harmonic mean of sum of first n natural numbers and sum of cubes of first n natural numbers is

The difference between the sum of the cubes of first n natural numbers and squares of first n natural numbers is

Join BYJU'S Learning Program