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Permutation: n Different Things Taken r at a Time

The sum of th...

Question

The sum of the digits at the ten's place of all the all the numbers formed with the digits $3, 4, 5, 6$ taken all at a time is

A

432

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B

108

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C

36

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D

18

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Solution

The correct option is C $108$
Every digit occurs $6$ times in all the numbers formed.
Therefore, the sum of the digits in the unit place $= 6 (3 + 4 + 5 + 6) = 108$

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