The sum of the digits in the unit place of all numbers formed with the help of 3,4,5,6 taken all at a time is

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432

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108

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144

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Solution

The correct option is C
108

If we fix 3 of the unit place, then the other three digits can be arranged in 3! ways. Similarly for 4, 5, 6.
Required sum $= 3! (3 + 4 + 5 + 6) = 6 \times 18 = 108$

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