The sum of the digits of a 3 digit number is subtracted from the number. The resulting number is always
A
Divisible by 6
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B
Not divisible by 6
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C
Divisible by 9
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D
Not divisible by 9
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Solution
The correct option is C Divisible by 9 Letx,yandzbethedigitsofthegivennumber.∴Thenumberis100x+10y+z.Sumofthedigitsisx+y+z∴Thedifferencebetweenthenumberandthesumofthedigitsis100x+10y+z−(x+y+z)=99x+9y=9(11x+y)∴Thisisdivisibleby9.Answer−9