The sum of the digits of a two digit number is 12. The number obtained by reversing its digits exceeds the given number by 18. Then the number is______
57
The sum of the digits of a two digit number is 12
⇒ x + y = 12……………(i)
The number obtained by reversing its digits exceeds the given number by 18.
⇒ 10y + x - (10x + y) = 18
⇒ y – x = 2……(ii)
Adding (i) and (ii), we have
2y = 14 ⇒ y = 7
x + 7 = 12 ⇒ x = 5
Then the number is 57