the sum of the digits of a two digit number is 12 . the number obtained by reversing the digits is 36 greater than the original number. find the number

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$D e a r S t u d e n t L e t t h e d i g i t o n t e n s p l a c e b e x a n d t h a t o n o n e s p l a c e i s y G i v e n x + y = 12 - - - - (1) 10 x + y = 10 y + x - 36 9 x - 9 y = - 36 9 y - 9 x = 36 y - x = 4 - - - - - (2) s u b s t r a c t i n g e q (1) a n d (2) x + y = 12 y - x = 4 w e g e t, 2 x = 8 x = 4 s u b s t i t u t e x = 4 i n (1) w e g e t y = 8 s o t h e o r g i n a l n u m b e r i s 48 R e g a r d s$

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the sum of the digits of a two digit number is 12 . the number obtained by reversing the digits is 36 greater than the original number. find the number

Dear StudentLet the digit on tens place be x and that on ones place is yGiven x+y =12 ----(1)10x+y =10y+x-369x-9y=-369y-9x=36y-x =4-----(2)substracting eq (1) and (2)x+y =12 y-x =4we get ,2x =8x=4substitute x=4 in (1)we get y =8so the orginal number is 48Regards