Question

The sum of the digits of a two digit number is $6$ and its ten's digit is twice its unit digit. Find the number.

• A. $58$
• B. $20$
• C. $42$
• D. $76$

Answer 1

The correct option is C $42$

Let the unit's digit be $x$, then the ten's digit = $2x$

Given sum of digits $=6$

$⟹x+2x=63x=6x=2$

Ten's digit $=2x=4$

Required number =$10\left(2x\right)+1\left(x\right)=10\left(4\right)+1\left(2\right)=42$