The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.

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Solution

Let the number be “ab”

Its value is 10a + b

a + b = 9 ---------- (1)

Also

9(10a + b) = 2(10b+a)

8a –b = 0 ---------- (2)

Solving, we get a= 1, b= 8

Hence our number is 18

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The sum of the digits of a two-digit number is 9. Also, twice this number is nine times the number obtained by reversing the order of the digits. Find the number.

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The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. The number is 18.

The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.[4 MARKS]

Q. The sum of the digits of two digit number is

9

. If nine times this number is equal to twice the number obtained by reversing the order of digits of the number. Find the numbers.

Question 2 (iii)
Form the pair of linear equations in the following problems, and find their solutions (if they exist) by the elimination method:
The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.

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The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.

Let the number be “ab” Its value is 10a + b a + b = 9 ---------- (1) Also 9(10a + b) = 2(10b+a) 8a –b = 0 ---------- (2) Solving, we get a= 1, b= 8 Hence our number is 18

Let the number be “ab”

Its value is 10a + b

a + b = 9 ---------- (1)

Also

9(10a + b) = 2(10b+a)

8a –b = 0 ---------- (2)

Solving, we get a= 1, b= 8

Hence our number is 18